AHU Sizing Guide — How to Calculate Airflow, Coil Capacity and Fan Power

Published on MEPMate  |  HVAC Engineering  |  AHU Selection

The Air Handling Unit (AHU) is the central component of any ducted HVAC system. It conditions outside and recirculated air — cooling, dehumidifying, filtering, and distributing it through the building ductwork. Selecting the right AHU requires calculating four key parameters: supply airflow, cooling coil capacity, chilled water flow rate, and fan power. This guide walks you through each step with worked examples.

AHU Components — What You Are Sizing

A typical chilled water AHU consists of:

  • Filter section: G4 pre-filter + F7 bag filter (for commercial); HEPA for healthcare
  • Cooling coil: Chilled water or DX coil to cool and dehumidify air
  • Heating coil: LPHW or electric for winter or reheating
  • Supply fan: Centrifugal or axial fan to overcome duct system resistance
  • Fresh air damper + return air damper: To mix outdoor and recirculated air
  • Drain pan: To collect condensate from the cooling coil

Step 1 — Calculate Supply Airflow

Supply airflow is determined from the sensible cooling load and the supply air temperature:

Supply Airflow (Sensible Only): Q = Qs / (ρ × Cp × ΔT) Q = Qs / (1.2 × ΔT) [simplified, in m³/s] Where: Qs = Total sensible cooling load (kW) ρ = Air density ≈ 1.2 kg/m³ at sea level Cp = Specific heat of air = 1.006 kJ/kg·K ΔT = Room temperature − Supply air temperature (°C) Typical: 12°C room temp difference Room = 24°C, Supply = 12°C → ΔT = 12°C For total heat (sensible + latent) using enthalpy method: Q = Total load (kW) / (ρ × Δh) Where Δh = enthalpy difference from room to supply air condition (kJ/kg)

Minimum Ventilation Airflow Check

Always verify the calculated airflow meets minimum ventilation requirements per NBC/ASHRAE 62.1:

  • Office spaces: minimum 10 L/s per person
  • Retail: 10 L/s per person + 3 L/s·m² area
  • Meeting rooms: 10 L/s per person

The supply airflow must satisfy both the cooling load requirement and the minimum ventilation requirement — whichever is larger governs.

Step 2 — Size the Cooling Coil

Coil Entering and Leaving Conditions

Coil Entering Air (Mixed Air) Condition: T_mix = (Q_fresh × T_outdoor + Q_return × T_room) / Q_total Typical design conditions: Outdoor air: 42°C DB / 28°C WB (Mumbai summer) Room air: 24°C DB / 17°C WB Fresh air %: 20-30% for typical commercial Coil Leaving Air (Supply Air) Condition: Cooling to 12°C DB / 11.5°C WB (approximately) This achieves the required room conditions Cooling Coil Capacity (Total): Q_coil = m_air × (h_entering - h_leaving) Q_coil = ρ × Q_supply × (h_entering - h_leaving) = 1.2 × Q_supply × Δh Where Δh = enthalpy difference across coil (kJ/kg) Typical: 30–50 kJ/kg for mixed air to supply air condition

Coil Face Area

Face Velocity: V_face = 2.0 to 2.5 m/s (recommended) Coil Face Area = Q_supply (m³/s) / V_face (m/s) Example: Q = 4 m³/s supply airflow V_face = 2.3 m/s Face Area = 4 / 2.3 = 1.74 m² Standard coil size: 1400mm × 1250mm = 1.75 m² ✓

Step 3 — Chilled Water Flow Rate

Chilled Water Flow Rate: Q_chw = Q_coil / (ρ_water × Cp_water × ΔT_chw) = Q_coil / (4.187 × ΔT_chw) [in L/s, Q_coil in kW] Standard chilled water temperatures: Flow (supply): 7°C Return: 12°C ΔT_chw = 12 - 7 = 5°C Example: If Q_coil = 120 kW: Q_chw = 120 / (4.187 × 5) = 120 / 20.93 = 5.73 L/s = 20.6 m³/h

Use our AHU Sizing Calculator to compute supply airflow, coil capacity, chilled water flow rate, and fan power in one step. Also check the HVAC Heat Load Calculator to first determine your building cooling load.

Step 4 — Fan Sizing (Static Pressure and Power)

Total External Static Pressure

The AHU fan must overcome the resistance of the entire duct system — supply ductwork, fittings, diffusers, return ductwork, and filters. Typical values for commercial buildings:

System ComponentTypical Pressure Drop
G4 pre-filter (clean)50–80 Pa
F7 bag filter (clean)80–120 Pa
Cooling coil (4-row)100–150 Pa
Supply ductwork (main)80–150 Pa
Diffuser and terminal20–50 Pa
Return ductwork50–100 Pa
Typical Total ESP350–650 Pa
Fan Motor Power: P_fan = (Q × ΔP) / (η_fan × η_motor × 1000) Where: Q = Airflow (m³/s) ΔP = Total static pressure (Pa) η_fan = Fan efficiency ≈ 0.65–0.75 (centrifugal) η_motor = Motor efficiency ≈ 0.88–0.93 Example: Q = 4 m³/s, ΔP = 500 Pa, η_fan = 0.70, η_motor = 0.90 P = (4 × 500) / (0.70 × 0.90 × 1000) = 2000 / 630 = 3.17 kW Select: 3.7 kW (5 HP) fan motor with VFD control

Worked Example — Full AHU Sizing

Project: Office floor, 800 m², Mumbai Cooling load: Sensible 95 kW, Latent 28 kW, Total 123 kW Occupancy: 80 people, Fresh air: 10 L/s/person = 800 L/s = 0.8 m³/s Step 1 — Supply Airflow: Q_supply = 95 / (1.2 × 12) = 95 / 14.4 = 6.6 m³/s Min ventilation airflow = 0.8 m³/s (80 persons × 10 L/s) Governs: 6.6 m³/s (cooling load governs) Step 2 — Coil Capacity: Mixed air enthalpy: 20% fresh air (42°C / 80 kJ/kg), 80% return (24°C / 48 kJ/kg) h_mixed = 0.20 × 80 + 0.80 × 48 = 16 + 38.4 = 54.4 kJ/kg Supply air enthalpy ≈ 32 kJ/kg (12°C, 95% RH) Δh = 54.4 - 32 = 22.4 kJ/kg Q_coil = 1.2 × 6.6 × 22.4 = 177.4 kW ≈ 50.4 TR Step 3 — Chilled Water Flow: Q_chw = 177.4 / (4.187 × 5) = 177.4 / 20.93 = 8.47 L/s = 30.5 m³/h Step 4 — Fan Power: ΔP_total = 500 Pa (assumed for this system) P_fan = (6.6 × 500) / (0.70 × 0.90 × 1000) = 3300/630 = 5.24 kW Select: 5.5 kW motor with VFD AHU Selection Summary: Airflow: 6.6 m³/s = 23,760 m³/h Coil load: 178 kW (50.5 TR) CHW flow: 30.5 m³/h (7°C / 12°C) Fan motor: 5.5 kW Face area: 6.6 / 2.3 = 2.87 m² → 1700 × 1700mm coil

AHU vs FCU — When to Use Which

ParameterAHUFCU
Typical capacity10–200+ kW0.5–10 kW
Fresh air handlingYes — central OA treatmentLimited (via separate DOAS)
FiltrationHigh efficiency (F7, HEPA)Basic G4 only
Zone controlComplex (VAV boxes needed)Simple (on/off or 3-speed)
Best forLarge open offices, malls, hospitalsHotel rooms, small offices

Common AHU Sizing Mistakes

  • Sizing only for sensible load and ignoring latent: The cooling coil must handle total heat (sensible + latent). Using only sensible load for coil selection results in an undersized coil that cannot dehumidify adequately in Indian humidity conditions.
  • Using too high a face velocity: Face velocities above 2.5 m/s cause moisture carryover — condensate droplets are blown into the ductwork, causing wet insulation and mould growth downstream.
  • Not sizing for dirty filter pressure drop: Fan ESP must be calculated at dirty filter conditions. Clean filter pressure drop × 2 is often used for the dirty condition to size the fan correctly.
  • Ignoring duct system balance: If the AHU serves multiple zones with different pressure drops, the longest and highest-resistance branch governs. Always size the fan for the critical path.

Conclusion

AHU selection is a four-step process: calculate supply airflow from cooling load and temperature difference, size the cooling coil for total heat removal and appropriate face velocity, calculate chilled water flow based on coil capacity and temperature differential, and finally size the supply fan for the system's total static pressure. Getting all four correct ensures your AHU performs reliably and efficiently throughout the building's lifecycle.

Speed up your AHU selection with the MEPMate AHU Sizing Calculator. Also use the Psychrometric Calculator to accurately determine mixed air and supply air enthalpies for precise coil duty calculations.